9(2x-y)²-6(2x-y) 1因式分解

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 11:55:07
9(x-y)^2-6(y-x)^2+1

9(x-y)^2-6(y-x)+1=9(x-y)^2+6(x-y)+1=[3(x-y)+1]^2=(3x-3y+1)^2

x^2-9y^2-2x+6y

=(x-1)^2-(3y-1)^2=(x-1+3y-1)(x-1-3y+1)=(x+3y-2)(x-3y)

9(x+y)^2-6(x+y)+1进行因式分解

9(x+y)^2-6(x+y)+1=【3(x+y)-1】²

因式分解3x^2(x-y)+6x(y-x)

3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)

计算:(x-y)^2*(y-x)^2*(x-y)^6

(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x

1、x(x-y)(x+y)-x(x+y)^2

1)x(x-y)(x+y)-x(x+y)^2=x((x-y)(x+y)-(x+y)^2)=x(x^2-y^2-x^2-2xy-y^2)=x(-2xy-2y^2)=-2xy(x+y)2)(2a+b)(2

已知方程组{2x+y=6 x+2y=9},求x+y与x-y的值

2x+y=6x+2y=9相加得3x+3y=15x+y=5相减得2x+y-x-2y=6-9x-y=-3

6(x+y)2-2(x-y)(x+y)因式分解

(x+y)ˆ2-2(x+y)(x-y)+(x-y)ˆ2=(x+y-x+y)^2=(2y)^4=4y^2如果满意请点击右上角评价点【满意】即可~再问:这个我看不懂,能不能写下来啊,谢

怎么因式分解6(x-y)-9-(x-y)∧2

原式=-[(x-y)^2-6(x-y)+9]=-(x-y-3)^2.

因式分解9x-6x(x-y)+x(x-y)^2

9x-6x(x-y)+x(x-y)^2=x[9-6(x-y)+(x-y)^2]=x(x-y-3)^2

9(X+Y)^2-6(X+Y)+1 (因式分解)

原式=(3x+3y-1)(3x+3y+1)标准的十字相乘法.

因式分解(x-y)^2-6(x-y)+9

    学习愉快!

化简:x-y/x+3y÷x^-y^2/x^2+6xy+9y^2-(xy/x+y)

[(x-y)/(x+3y)]/[(x^2-y^2)/(x^2+6xy+9y^2)]-xy/(x+y)=(x-y)/(x+3y)*(x+3y)^2/(x-y)(x+y)-xy/(x+y)=(x+3y)/

化简:x-y/x+3y÷x^2-y^2/x^2+6xy+9y^2-2y/x+y

原式=(x-y)/(x+3y)×[(x+3y)^2/(x+y)(x-y)]-2y/(x+y)=(x+3y)/(x+y)-2y/(x+y)=(x+3y-2y)/(x+y)=(x+y)/(x+y)=1

9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y的平方(x-y)(x+1),因式分解

第一项与第三项先合并9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y^2*(x-y)(x+1)=(x-y)(x+1)(9xy+6y^2)-3y(x-y)(3x+2y)=(x-y)(x+1

计算:(2/3x√9x+6x√y/x)+(y√x/y-√1/x)

(2/3x√9x6x√y/x)(y√x/y-x²√1/x)=2/3*x*3√x6x*√(xy)/xy*√(xy)/y-x²√x/x=2x√x6√(xy)√(xy)-x√x=x√x7

(x-2xy)*(-xy+2y*y)-(3x*x-2xy)(x-9xy+6y*y)

原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&

x+y=3 x+2y=9 3/x+1=y y-x=3 y=2x-3 y-3x=1 2(x+1)-y=6 7x-5y=-9

x+y=3则y=3-x带入x+2y=9解得x=-3,y=6剩下的都这样解