作业帮1 1 x^4
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1/（x^2-7x+10)+1/(x^2-x-2)+1/(x^2+5x+4)+1/(x^2+11x+28)=[1/(x-5)-1/(x-2)+1/(x-2)-1/(x+1)+1/(x+1)-1/(x+
6x+4x-11=2.96x+4x=2.9+1110x=13.9x=1.39
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583
【解法一】【解法二】5x(x+7)(x+4)=5x(x^2+11X)5x(x²+11x+28)-5x(x²+11x)=05x^3+55x^2+140x=5x^3+55x^25x(x
去掉绝对值原式=x+1-x-2+x+3-x-4+x+5-x-6+x+7-x-8+x+9-x-10+x+11-x-12+x+13=x+13-6=x+7=π/3+7
3X²+4X+8=2X+11移项3X²+2X-3=0（X+1/3）²—1-1/9=0（X+1/3）²=10/9解之得：X=(根号10-1)/3或者X=—（根号1
5x(x+7)(x+4)=5x(x^2+11X)5x^3+55x^2+140x=5x^3+55x^2140x=0x=0
题目有问题在实数范围内无解你算错了x^2+2x=-20(x+1)^2=-19任意数平方要>=0所以无解
移项x²+2x=2x²+2x+1=2+1(x+1)²=3x+1=±√3x=-1-√3,x=-1+√3
6x²-9x-4x+2x²=-2x+8x²-11-9x-4x﹢2x=-11-11x=-11x=1
x(2x-3)+3x+3x(x-2)=5x(x-4)+112x²-3x+3x+3x²-6x=5x²-20x+115x²-6x=5x²-20x+115x
X2+2X-3=0=(X+3)*(X-1)X=-3或1
提示,设t=（x^2+3x)/(x^2+X-4)算出t再求x
是方程,解是所有数,包括实数虚数
13x-8x-20=2x+223x=42x=14
6x³-11x²+x+4=6x³-6x²-5x²+x+4=6x³-6x²-5x²+5x-4x+4=6x²(x-
17.6x-3.6x(6x-5)=4；分解等式：4x+3.6x-3.6x(6x-5)=4,进一步得：4(x-1)+3.6x(1-6x+5)=0,再合并得：4（x-1）+9.6x（1-x）=0；解得x=
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