3x 4y=5,5x-6y=33用代入法解下列方程组

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x+y/2+x-y/3=6,4(x+y)-5(x-y)=2用加减消元法解方程组

1,x+y/2+x-y/3=6即:5x-y=36①4(x+y)-5(x-y)=2即:-x+9y=2②①+②*5==可接2,先化整:3(x+y)+2(x-y)=36①4(x+y)-5(x-y)=2②①*

已知4x的平方加y的平方减4x加6y加十等于零,求4x的平方减12x4y加9y的平方的值.

我怕来不及,等等发给你!再问:慢慢来,,,,,,再问:还没好??

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

把多项式2x3y2-3x2y3-5x4y+6xy4-5按x的降幂排列是______.

多项式2x3y2-3x2y3-5x4y+6xy4-5中,x的系数依次3,2,4,1,按x的降幂排列是-5x4y+2x3y2-3x2y3+6xy4-5.

3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27

化简得:-x+7y=11①7x+3y=27②①式×7得:-7x+49y=77③②+③得:52y=104∴y=2代入①得:x=3∴x=3,y=2再问:亲,是代入法哦!再答:代入法①式得3x+3y-4x+

{x=5y 3x+6y=42

x=5y代入3x+6y=42得到15y+6y=4221y=42y=2那么x=5y=10希望能帮你忙,不懂请追问,懂了请采纳,谢谢

已知x.x+y.y-6x-8y+25=0,求3x.x+5y的值

可以得出x.x+y.y-6x-8y+25=x.x-6x+9+y.y-8y+16=(x-3).(x-3)+(y-4).(y-4)=0因为(x-3).(x-3)>=0,(y-4).(y-4)>=0所以x=

已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y

在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域;然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域;最后作2x+y≤10对应的直线2x+y

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

解二元一次方程组:{5(x+y)+3(x-y)=2{7(x+y)-3(x-y)=-6

{5(x+y)+3(x-y)=2{7(x+y)-3(x-y)=-6原方程组化简得﹛4x+y=1(1)2x+5y=-3(2)(1)×5得20x+5y=5(3)(3)-(2)得18x=8x=4/9代入(1

若5x+3y=3x+4y=x+2y+6,则x+y=___

3x+4y=x+2y+62x-x+4y-2y=62x+2y=6x+y=6/2x+y=3

解方程组 {(x+y)/2+(x-y)/3=6 5(x+y)-2(x-y)=4

(x+y)/2+(x-y)/3=6①5(x+y)-2(x-y)=4②由①得3x+3y+2x-2y=365x+y=36y=36-5x③由②得5x+5y-2x+2y=43x+7y=4④③代入④得3x+25

解方程组:x+y/2+x-y/3=6 4(x+y)-5(x-y)=12

设a=x+y,b=x-y原方程组为:a/2+b/3=6,即3a+2b=36,即:12a+8b=1444a-5b=12,即:12a-15b=36相减得:23b=108,得:b=108/23,再得:a=1

先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y

解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy

解方程组 X+Y/2+X-Y/3=6 4[X+Y]-5[X-Y]=2

先将第一个等式整理得12X+Y=36,第二个等式整理得-X+9Y=2,由第一个等式得Y=36-12X,通过换元法得-X+9(36-12X)=2,解出X=322/109,再把X=322/109代入-X+

4x-2y-6y*-y-3x+5y* *=2 就是平方

题意不清什么是平方,*吗?那么**代表三次方还是4次方呢

(5x+3y)(3y-5x)-(4x-y)(4y+x)=

(5x+3y)(3y-5x)-(4x-y)(4y+x)=(3y)^2-(5x)^2-(4x^2+15xy-4y^2)=9y^2-25x^2-4x^2-15xy+4y^2=13y^2-15xy-29x^

若-2x3m+1y2n与4xn-6y-3-m的积与-4x4y是同类项,求m、n.

∵-2x3m+1y2n•4xn-6y-3-m=-8x3m+n-5y2n-3-m,又∵-2x3m+1y2n与4xn-6y-3-m的积与-4x4y是同类项,∴3m+n−5=42n−3−m=1,解得:m=2

x+y=3 x+2y=9 3/x+1=y y-x=3 y=2x-3 y-3x=1 2(x+1)-y=6 7x-5y=-9

x+y=3则y=3-x带入x+2y=9解得x=-3,y=6剩下的都这样解