3a²-5a 2-6a² 6a-3其中a
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解;∵3a2-a-2=0,∴3a2-a=2,∴5+2a-6a2=5-2(3a2-a)=5-2×2=1.故答案为:1.
∵a2+3a+1=0,∴a2+3a=-1,∴原式=3a3+(a2+5)(a2-1)-a(5a+6)=3a3+a4+4a2-5-5a2-6a=a4+3a3+4a2-5-5a2-6a=a2(a2+3a)+
a2-b2+a+5b-6=(a+1/2)^2-(b-5/2)^2不等于0(a+1/2)^2不等于(b-5/2)^2a+1/2不等于b-5/2a+3不等于
(a^2-9)/(a^2+6a+9)+(a-3)/(a^2+3a)-(a-a^2)/(a-1)=(a+3)(a-3)/(a+3)^2+(a-3)/[(a+3)a]+a(a-1)/(a-1)=(a-3)
∵实数a满足a2-2a-1=0,∴a2-2a=1,∴3a2-6a+5=3(a2-2a)+5=8.故答案为:8.
原式=[(a²-4)/(a²-4a+3)]×[(a-3)/(a²+3a+2)]={(a-2)(a+2)/[(a-1)(a-3)]}×{(a-3)/[(a+1)(a+2)]
(a²-a-6)/(a+2)-√(a²-2a+1)/(a²-a)=(a-3)(a+2)/(a+2)-(a-1)/[a(a-1)]=a-3-1/a=1/2+√3-3-1/(
证明:a²-b²+a+5b-6≠0a²+a+1/4-1/4-b²+5b-25/4+25/4-6≠0(a+1/2)²-(b-5/2)²≠0a+
(2a+6)/(a2-4a+4)×(a-2)/(a2+3a)-(1/a-2)=2(a+3)/(a-2)²×(a-2)/[a(a+3)]-1/(a-2)=2/[a(a-2)]-1/(a-2)=
括号打少一半,麻烦出了一堆4A+{2B-[5A-(3B-2C)+6B]+3C}=4A+[2B-(5A-3B+2C+6B)+3C]=4A+2B-5A+3B-2C-6B+3C=-A-B+C代入ABC原式=
4A+{2B-[5A-(3B-2C)+6B]+3C}=4A+{[2B-(5A-3B+2C+6B)]+3C}=4A+2B-5A+3B-2C-6B+3C=-A-B+C然后将A、B、C分别代入就行了
原式=(a²+4a+4-6-3a)/(a²+4a+4)×(a²+2a)/(4a-4)=(a+2)(a-1)/(a+2)²×a(a+2)/4(a-1)=a/4
∵a2-2a=3,∴3a2-6a-8=3(a2-2a)-8=3×3-8=1,∴3a2-6a-8的值为1.
(a-1)-(3a²-2a+1)=a-1-3a²+2a-1=-3a²+3a-2A=2(2-x)+1=4-2x+1=5-2x代入A-2b=x-15-2x-2b=x-12b=
(a^2+5a+2+1)(a^2+5a-2)-6=(a^2+5a+2)(a^2+5a-2)+a^2+5a-2-6=(a^2+5a)^2-4+a^2+5a-8=(a^2+5a)^2+a^2+5a-12=
∵a2-2a=-2,∴3a2-6a+3=3(a2-2a)2+3=3×(-2)+3=-3,故答案是-3.
(a2-1)/(a2+2a+1)除以(a2-a)/(a+1)(a-2/(a+3)除以(a2-4)/(a2+6a+9)=﹙a²-1﹚/﹙a²+2a+1﹚×﹙a+1﹚/﹙a²
(1)(4a³b-10b³)+(-3a²b²+10b³)=4a³b-10b³-3a²b²+10b³=
原式=5a2-[a2+5a2-2a-2a2+6a]=5a2-[4a2+4a]=5a2-4a2-4a=a2-4a.
(a2-a)a2-2a-3÷a(a-3)=a(a-1)(a+1)(a-3)×a-3a=a-1a+1当a=2+1时,原式=22+1+1=22+2=2-1.故填空答案:2-1.