分解因式,2x2-7x 6
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7x^2-63=7(x^2-9)=7(x+3)(x-3)4x^2-16=4(x^2-4)=4(x+2)(x-2)(2x+1)^2-x^2=4x^2+4x+1-x^2=3x^2+4x+1=(3x+1)(
1楼说实话答的不错,可是还是有些题...有些题和2楼答的一样x^3-x^2-x-2=x^3-2x^2+x^2-x-2=x^2(x-2)+(x-2)(x+1)=(x^2+x+2)(x-2)x^5+x+1
x的三次方+x2-2=(x³-1)+(x²-1)=(x-1)(x²+x+1)+(x-1)(x+1)=(x-1)(x²+2x+2)再问:(x三次方-1)如何化成(
分解因式下:X4-2X2-8=(x²-4)(x²+2)=(x+2)(x-2)(x²+2)X2-3XY+2Y2=(x-2y)(x-y)2X2-7X+3=(2x-1)(x-3
2(x-3)=x²-9(x²-9)-2(x-3)=0(x-3)(x+3)-2(x-3)=0(x-3)[(x+3)-2]=0(x-3)(x+1)=0x-3=0或x+1=0x1=3x2
2x²+3x+2=2[x-﹙-3+√7i﹚/4][x-﹙-3-√7i﹚/4]=2[x+﹙3-√7i﹚/4][x+﹙3+√7i﹚/4]
∵x的多项式x2+8x+k分解因式后的一个因式是x-2, 当x=2时多项式的值为0,即22+8×2+k=0,∴20+k=0,∴k=-20.∴x2+8x+k=x2+8x-20=(x-2)(x+
一式无法分解二式(x+1)*(x^2+x+1)*(x^2-x+1)三式无法分解
∵2x2-xy-6y2=(x-2y)(2x+3y),∴可设2x2-xy-6y2+7x+7y+3=(x-2y+a)(2x+3y+b)a、b为待定系数,∴2a+b=7,3a-2b=7,ab=3,解得a=3
x2-x-2=(x-2)(x+1).故答案为:(x-2)(x+1).
x2-y2-2y-1,=x2-(y2+2y+1),=x2-(y+1)2,=(x+y+1)(x-y-1).
2x2-4x+2,=2(x2-2x+1),=2(x-1)2.
2x2-4x-9是2x^2-4x-9这样吗用公式法(或者配方法)配方法2x^2-4x-9=2(x^-2x+1)-11=[根号2(x-1)]^2-(根号11)^2=[根号2*(x-1)+根号11]*[根
原式=8x2-16y2-7x2-xy+xy=x2-16y2=(x+4y)(x-4y).
解方程x2+2x-4=0,得:x=-1±5,则x2+2x-4=(x+1+5)(x+1-5).故答案是:(x+1+5)(x+1-5).
(x2-2x)2-7(x2-2x)+12=(x2-2x-4)(x2-2x-3)=(x2-2x-4)(x-3)(x+1).
x2-a2-2a-2x=(x^2-2x+1)-(a^2+2a+1)=(x-1)^2-(a+1)^2=(x-1+a+1)(x-1-a-1)=(x+a)(x-a-2)
实数范围:无复数范围:(x+yi)(x-yi)-(x+yi)(x-yi)
x2-2xy+y2-9,=x2-2xy+y2-9,=(x2-2xy+y2)-9,=(x-y)2-32,=(x-y+3)(x-y-3).
令a=x²-5x原式=a(a-2)-24=a²-2a-24=(a-6)(a+4)=(x²-5x-6)(x²-5x+4)=(x-6)(x+1)(x-1)(x-4)