1乘3分之2加乘5分之2加5乘7分之2加等等加97乘99分之2等于

1/(1*2*3)+1/(2*3*4)an=1/[n(n+1)(n+2)]=[(n+2)-(n+1)]/[n(n+1)(n+2)]=1/n(n+1)-1/n(n+2)=[1/n-1/(n+1)]-(1

(1*2*3+2*4*6+3*6*9+4*8*12)/(3*4*5+6*8*10+9*12*15+12*16*20)=(1*2*3)(1+8+27+64)/(3*4*5)(1+8+27+64)=(1*

1,=(1/2)×(1/1×2+1/2×3)+(1/2)×(1/2×3-1/3×4)+……+(1/2)×(1/48×49-1/49×50)=(1/2)×(1/1×2+1/2×3+1/2×3-1/3×4

1/2×3+1/3×4+……+1/99×100=1/2-1/3+1/3-1/4+……+1/99-1/100=1/2-1/100=49/100

答：2/(1*3)+2/(3*5)+2/(5*7)+2/(7*9)+2/(9*11)=1/1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11=1-1/11=10/11

=1-1/2+1/2-1/3+1/3-1/4+……+1/9-1/10=1-1/10=9/10

1乘2分之1加2乘3分之1加3乘4分之1加4乘5分之1加5乘6分之1加6乘7分之1=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7=1-1/7=6/7=7分

原式=1/2*(1/2*3-1/3*4+1/3*4-1/4*5+.+1/8*9-1/9*10)=1/2*(1/6-1/90)=1/2*(14/90)=7/90

5/1×2+5/2×3+5/3×4+……+5/48×49+5/49×50=5(1/1×2+1/2×3+1/3×4+……+1/48×49+1/49×50)=5(1/1-1/2+1/2-1/3+1/3-1

=1/1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+……+1/19-1/21=1-1/21=20/21再问：这样不对吧再答：裂项看中间任意一个如2/11×13=(13-11)/11×13

=1-2分之1+2分之1-3分之1+3分之1-4分之1+……+99分之1-100分之1=1-100分之1=100分之99

1/2*3+1/3*4+1/4*5+……+1/49*50=(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+……+(1/49-1/50)=1/2-1/3+1/3-1/4+1/4-1/5+……

4949/19800因为1/n(n+1)(n+2)=1/n(1/(n+1)-1/(n+2))=1/n-1/(n+1)-1/2(1/n-1(n+1))

2+5\84

1*3*5+3*9*15+7*21/35*2*3+3*6*9+7*14*21=15+405+25.2+162+2058=2665.2或把3分别提出,变成3（5+9*15+14*24/35+6*9+7*

原式=1/2-1/3+1/3-1/4+1/4-1/5+...+1/2010-1/2011+1/2011-1/2012=1/2-1/2012=1005/2012

你丫的就十来混经验的再问：会不会啊，急急急我要答案再答：等于一1+2/3x1—-2/3x1.....=1+2/3-2/3+2/5-2/5......=1懂？再问：不对，答案是297分之101，但是我要

2/(1×2×3)+2/(2×3×4)+...+2/(28×29×30)=2*1/2*[1/(1×2)-1/(2×3)+1/(2×3)-1/(3×4)+...+1/(28×29)-1/(29×30)]

看到你问过一个类似的题目,三个连续自然数相乘的倒数,此题类似,考虑通式：（2n+3)/[n(n+1)(n+2)(n+3)]=(n+n+3)/[n(n+1)(n+2)(n+3)]=1/[(n+1)(n+

=1*2*3(1+2*2*2+7*7*7)/[1*3*5(1+2*2*2+7*7*7)]=1*2*3/(1*3*5)=2/5