(2x-1)(3x 2)=0化成一般形式
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令a=x+1/x两边平方a²=x²+2+1/x²所以x²+1/x²=a²-2所以2(a²-2)-3a-1=02a²-3a
设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x
后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
令t=x+1/x则该方程可化为2t^2-3t-5=0解得t=-1或5/2x+1/x=-1,无解x+1/x=5/2,解得x=2或1/2所以x=2或1/2
1.令t=x+1/x则t^2=x^2+1/x^2+2代入方程:2(t^2-2)-3t-1=02t^2-3t-5=0(2t-5)(t+1)=0t=5/2,-1当t=5/2时,由x+1/x=5/2得x=2
(1)(x+1)^2+y^2=0,不是圆方程(2)x^2+(y+a)^2=1-a^2,当-1
由条件左右除以x,得x+1/x=3平方得:x2+1/x2+2=9所以x2+1/x2—2=5所求值为根号5
原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以:(x+1)(x+2)(x-3)得:(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2
去括号:3x2-3=2x,移项:3x2-2x-3=0故答案为:3x2-2x-3=0.
y=-2x2+4x+3=-2(x^2-2x+1)+2+3=-2(x-1)^2+5
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
5x²-3x-5=0△=3²-4×5×(-5)=109x=[﹣(﹣3)±√109]/5由原方程可得所求式子=(x+5)-1/(x+5)所求式子=(118±6√109)/25-25/
∵x2+6x=-3,∴x2+6x+9=-3+9,∴(x+3)2=6.故选A.
通分:(x^2-3x)+(2x-1)(x+1)=0化简:3x^2-2x-1=0x1=1(舍去,分母不为0)x2=-1/3
x²-3x+2=0(x-1)(x-2)=0因为分母x-1≠0所以x-2=0x=2原式=x(x-1)/(x-1)*(x+1)(x-1)/(x-1)²=x*(x+1)/(x-1)=2*
3x^2+15x-2+2(x^2+5x+1)^1/2=03(x^2+5x+1)+2(x^2+5x+1)^1/2-5=0另(x^2+5x+1)^1/2=y3y^2+2y-5=0y1=1y2=-5/3(舍
∵将圆x2+y2-2x-2=0化成标准方程,得(x-1)2+y2=3,∴圆x2+y2-2x-2=0的圆心为C(1,0),半径r=3.∵直线3x-y+m=0与圆x2+y2-2x-2=0相切,∴点C到直线
十字相乘法第一个:1-211第二个:211-3
你好x²+3x-1=0两边同除以xx+3-1/x=0x-1/x=-3两边平方得x²+1/x²-2=9x²+1/x²=11x²+1/x