5x2-3x-5=0,求5x2-2x-1/(5x2-2x)=多少?
5x2-3x-5=0,求5x2-2x-1/(5x2-2x)=多少?
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x
x2-5x+1=0则x2+x2/1
已知x2-5x=14,求2x2-x-2x+1-[x2+2x+1]+1的值.
已知X2-5X=3,求(X-1)(2x-1)-x(x+3)+15/x2-3的值
5x2—[x2+(4x—x2)—2(x2—3x)]
1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/(x+4)
(x2+5x+4)2+2(x2+5x+4)2+1=(x2+.
(-2x2+3x)-[5x-(2x2+1)-x2].
解分式方程:2/x2+5x+6 + 3/x2+x-6=4/x2-4
不等式:(x2+3x+3)/(x2+2x+5)
已知x1,x2是方程x^2+5x+1=0的两个实数根.求x1^2*x2+x2^2*x2的值?