作业帮1x2/1+2x3/1+3x4/1+.+2009x2010/1=? 2x4/1+4x6/1+6x8/1+.+2010x2
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/10 18:07:06
1x2/1+2x3/1+3x4/1+.+2009x2010/1=? 2x4/1+4x6/1+6x8/1+.+2010x2012/1=?
很急!1!
很急!1!
1x2/1+2x3/1+3x4/1+.+2009x2010/1
=1-2/1+2/1-3/1+3/1-4/1+……+2009/0-2010/1
=1-2010/1
=2010/2009
2x4/1+4x6/1+6x8/1+.+2010x2012/1
=2/1x(2/1-4/1+4/1-5/1+5/1-8/1+……+2010/1-2012/1)
=2/1x(2/1-2012/1)
=4024/1005
=1-2/1+2/1-3/1+3/1-4/1+……+2009/0-2010/1
=1-2010/1
=2010/2009
2x4/1+4x6/1+6x8/1+.+2010x2012/1
=2/1x(2/1-4/1+4/1-5/1+5/1-8/1+……+2010/1-2012/1)
=2/1x(2/1-2012/1)
=4024/1005
1x2/1+2x3/1+3x4/1+.+2009x2010/1=? 2x4/1+4x6/1+6x8/1+.+2010x2
1x2+2x4+3x6+4x8 ------------------------------- 2x3+4x6+6x9+
1x2+2x4+3x6+.+1005x2010
（1x2+2x4+3x6+4x8）/（2x3+4x6+6x9+8x12)
x8+x7+x6+x5+x4+x3+x2+x+1因式分解
1x2+2x4+3x6+4x8+5x10+.+20x40 怎么算?
1x2+2x4+3x6+4x8+5x10+.+20x40 简便计算
1.如果1+X+X2+X3=0,求X+X2+X3+X4+X5+X6+X7+X8的值为?
一道数学题:如果1+x+x2+x3=0,求x+x2+x3+x4+x5+x6+x7+x8的值
计算：1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7+1/7x8+1/8x9+1/9x10.
1x1-2x2+3x3-4x4+5x5-6x6.-100x100+101x101
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