log3(4)×log4(3)×log3(m)=log4(16)
log3(4)×log4(3)×log3(m)=log4(16)
设log3(4)*log4(m)=log4(16),求m
设log3(4)*log4(8)*log8(m)=log4(16)
(log2 3+log4 27)(log3 4+log27 16)
若log3(4)×log4(8)×log8(m)=log4(16).则m等于?谢谢
log3 4×log4 8×log8 m=log4 16,则m=( )(注:3,4,8是底数)请写出详细过程,
(log2 3+log4 27)*(log3 4+log9 8)=
关于对数的简单计算log3^4(以3为底的4的对数)×log4^8×log8^m=log4^16 求m的值(带过程)
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
log3(4)·log4(8)·log8(m)=log4(16)则m=
log3 4*log4 8*log8 m=log4 16,则m为[ ]
若log3 4*log4 8*log8 m=log4 16求m