f(x)=Asin^2(wx+φ)(A>0,w>0,0
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/29 00:12:01
f(x)=Asin^2(wx+φ)(A>0,w>0,0
f(x)=Asin^2(wx+φ)=A*[1-cos (2wx+2φ)]/2=-A/2*cos (2wx+2φ)+A/2.
因为A>0,所以当cos (2wx+2φ)=-1时,f(x)最大=A/2+A/2=A=2.
所以f(x)=-cos (2wx+2φ)+1.又图像两相邻对称轴距离为2,所以T=4.
又T=2π/2w=4,w=π/4.
所以f(x)=-cos (π/2*x+2φ)+1.
又f(x)过点(1,2),代入上式,得2=-cos (π/2*1+2φ)+1,解得
π/2+2φ=2kπ-π,φ=kπ-3π/4.又0
因为A>0,所以当cos (2wx+2φ)=-1时,f(x)最大=A/2+A/2=A=2.
所以f(x)=-cos (2wx+2φ)+1.又图像两相邻对称轴距离为2,所以T=4.
又T=2π/2w=4,w=π/4.
所以f(x)=-cos (π/2*x+2φ)+1.
又f(x)过点(1,2),代入上式,得2=-cos (π/2*1+2φ)+1,解得
π/2+2φ=2kπ-π,φ=kπ-3π/4.又0
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