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解方程1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/09 02:53:33
解方程1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)
要求用到规律:1/n(n+1)=1/n-1/(n+1)
1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)
1/(x-3)-1/(x-2)-1/(x-4)+1/(x-1)+1/(x-2)-1/(x-1)=1/(x-4)
1/(x-3)-1/(x-4)=1/(x-4)
1/(x-3)=2/(x-4)
2(x-3)=x-4
2x-6=x-4
x=2
检验是增根
所以原分式方程无解