已知函数f(x)=sin(x+π/6)cos(x+π/6)如何把这种函数化简
已知函数f(x)=sin(x+π/6)cos(x+π/6)如何把这种函数化简
已知函数f(x)=cos^2(x-π/6)-sin^2x化简
已知函数f(x)=sin(2x-π/6)+cos^2 x
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+2cos²x
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+2cos²x
已知函数f(x)=sin(2x+π/6)+sin(2x+π/6)+2cos²x
已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x
已知函数f(x)=cos(2x-π\3)+sin²x-cos²x
已知函数f(x)=cos^2(x-π/6)-sin^2
已知函数f(x)=sin(x+π6)−cos(x+π3)+cosx,
已知函数f(x)=cos(π/6-2x)+cos(2x+π/6)+sin(2x+π/3)-sin(π/3-2x).
已知函数f(x)=2cos x sin(x+pai/6)-sin^2x+cos^2x.