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1\3+1\6+1\10+1\15+1\21+1\28+1\36+1\45+1\50+1\55

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/12 08:50:34
1\3+1\6+1\10+1\15+1\21+1\28+1\36+1\45+1\50+1\55
请写清过程,不要省略
先提取公因数2,然后再进行裂项求和即可.
原式=2*(1/6+1/12+1/20+1/30.+1/110+1/100)
=2*[(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)+.+(1/10-1/11)+1/100]
=2*[1/2-1/11+1/100] 消去中间项
=2*461/1100
=461/550
再问: 为什么?看不懂哎 怎么得数又变了
再答: 我再写详细点!稍等! 因为1/6=1/2-1/3,1/12=1/3-1/4,1/20=1/4-1/5,1/42=1/6-1/7…… 原式=2*(1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90+1/100+1/110) =2*(1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90+1/110+1/100) =2(1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+1/10-1/11+1/100) =2*(1/2-1/11+1/100) 消去中间项 =2*461/1100 =461/550 我发觉1/100无法消去,如果题目没有抄错就是上面的结果。 之前看漏了1/50,所以算的是: 1\3+1\6+1\10+1\15+1\21+1\28+1\36+1\45+1\55 =2*(1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90+1/110) =2*(1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90+1/110) =2(1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+1/10-1/11) =2*(1/2-1/11) 消去中间项 =2*9/22 =9/11 不明白可追问! 请采纳!谢谢!