计算 2xy[4x²y²-3y（xy+x²y）-xy²]

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/04/28 04:30:26

计算 2xy[4x²y²-3y（xy+x²y）-xy²]
（2x-x²-3）（x³-x²-2）
（x²）³-2x³[x³-x²（4x+1）]
（-1/3xy）²·[xy（2x-y）-3x（xy-y²）]

2xy [4x²y²-3y(xy+x²y)-xy²]
= 2xy [4x²y²-3xy²-3x²y²-xy²]
= 2xy [x²y²-4xy²]
= 2x³y³-8x²y³
（2x-x²-3）（x³-x²-2）
= (-x²+2x)(x³-x²) - 3(x³-x²) - 2(-x²+2x)+6
= -x³ (x-2)(x-1) - 3x³+3x²+2x²-4x+6
= -x³ (x²-3x+2) - 3x³+3x²+2x²-4x+6
= -x^5+3x^4-2x³ - 3x³+3x²+2x²-4x+6
= -x^5+3x^4-5+5x²-4x+6
（x²）³-2x³[x³-x²（4x+1）]
= x^6-2x³(x³-4x³-x²)
= x^6-2x³(-3x³-x²)
= x^6+ 6x^6+2x^5
= 7x^6+2x^5
（-1/3xy）²·[xy（2x-y）-3x（xy-y²）]
= (1/9x²y²)·(2x²y-xy²-3x²y+3xy²)
= (1/9x²y²)·(-1x²y+2xy²)
= -1/9x^4y³ +2/9x³y^4

计算：(xy-x²)×x-y/xy 计算 2xy[4x²y²-3y（xy+x²y）-xy²] 计算：x²+2xy+y²/xy-y².x²-2xy+y²/xy+y&# 计算：（xy-x²）乘 x-y分之xy 计算：（-7x²y）（2x²y-3xy³+xy） 3x²y+xy²-[2xy²-4x²y+（x²y-2xy²） x-y/x²÷x²-2xy+y²/xy*（xy-x²）计算；（xy-x²）÷x²-2xy+y²/xy · x-y/x² 计算 (x²+2xy+y²）（x²-xy+y²）² 计算：2x+2y分之3y + x²+xy分之2xy (2x²y-3xy²)-3(x²y-2xy²)+2（x²y-4xy&# 分式计算:（x²+2xy+y²）/（x²y+xy）*y/（x+y）