高一计算题(0.0081)的-1/4次-1+log4的25+log8的4/125=

高一计算题(0.0081)的-1/4次-1+log4的25+log8的4/125= 你说lo5*lo8=3 log8(2）*log2(64) 依你的算法是log8(2)*4=1*log4(64)=3 你认 log4 8-log8 4=? log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( (log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方 (log8^27)/(log4^9)的值 log4^25+log8^8/125,最后的答案是等于一的, 化简log3(4)*log4(5)*log5(8)*log8(9)的结果是? log3 4*log4 8*log8 7*log7 m=1og3 18 求M 等于多少. 已知½log8（a）+log4（b）=5/2,log8(b)+log4(a^2)=7 求ab的值 化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根) (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根