lim(x→∞)[(a x^2)/x+1]+bx=lim(x→∞)(a x^2)+bx(x+1) / x+1=lim(x

lim(x→∞)[(a x^2)/x+1]+bx=lim(x→∞)(a x^2)+bx(x+1) / x+1=lim(x x→+∞,lim（1+a/x)^x=? 已知lim(x→1)(ax^2+bx=c)/(x-1)(x-2)=1,求a,b 设f(x)=lim(n→∞)(x^2n-1+ax^2+bx)/（x^2n）+1是连续函数,求a和b的值. 几道求极限的高数题,lim1/x(tanπx/(2x+1)) x→∞lim x(x^x-1)x→0+lim(x^x^x- 极限计算lim(x→0)[(1/1+x)-a-2bx]/2x=2为什么能推断出lim(x→0)(1/1+x)-a=0? lim(x→∞)[sinx/x+xsin(1/2x)] 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim(x^2+1/x^2-2x)^x=? 洛必达法则(1)条件?(2)lim(x->0)P(x)/Q(x)=?已知:lim(x->0)P(x)=A(x),lim( 求极限 lim [(3+x)/(6+x)]^[(x-1)/2]= x→∞ 极限lim(x→∞)[(1+x)/x]^2x=