Main() {int x[][4]={1,2,3,4,5,6,7,8,3,9,10,2,4,2,9,6},s=0,k=
Main() {int x[][4]={1,2,3,4,5,6,7,8,3,9,10,2,4,2,9,6},s=0,k=
main(){int x[]={1,2,3,4,5,6,7,8,9}int s,i,*p;s=0;p=&x[0];fpr
(5)main( ) { int k; int a[3][3]={1,2,3,4,5,6,7,8,9}; for(k=0
#define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k
Main() { Int i,s=0,t[]={1,2,3,4,5,6,7,8,9};
#define N 10 main() { int a[N]={1,2,3,4,5,6,7,8,9,10} int i,
main(){ int a[3][3]={1,2,3,4,5,6,7,8,9},m,k,t; for (m=0;m
main() { int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int *b; b=a;
int main() { int a[9] = {1,2,3,4,5,6,7,8,9}; int b[9] = {1,2
下列程序的输出结果是int main(void){int a[10] = {0,1,2,3,4,5,6,7,8,9},
main() {int a[5]={2,4,6,8,10},*p,**k; p=a; k=&p; printf("%d"
main() {int a【5】={2,4,6,8,10},*p,**k; p=a;k=&p;