作业帮[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/10 05:16:55
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简
结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
3k^2+11k+10
=（3k+5）(k+2)
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2)
=[k(k+1)/12]（3k+5）(k+2)+(k+1)(k+2)
=(k+1)(k+2)[k(3k+5)/12+1]
=(k+1)(k+2)[k(3k+5)+12]/12
=(k+1)(k+2)(3k^2+5k+1)/12
=（3k+5）(k+2)
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2)
=[k(k+1)/12]（3k+5）(k+2)+(k+1)(k+2)
=(k+1)(k+2)[k(3k+5)/12+1]
=(k+1)(k+2)[k(3k+5)+12]/12
=(k+1)(k+2)(3k^2+5k+1)/12
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简
1k、2k、3k是什么意思
（4*k^3+11k+12*k^2+3)/(k+1)怎么化简到4(k+1)^2-1?
K-1+K+2+K/3+K*3=2001
请问1^k+2^k+3^k+.+n^k=?
3×k×k-2k-1=-1.k等于
1^k+2^k+3^k+.+n^k 有无表达式
求证：lim1^k+2^k+3^k+4^k+.n^k/n^(k+1)=1/k+1
[k*(2-4k)/(1+2k)]+2k+1
当k等于?时,3k(2k-5)+2k(1-3k)=52
证明(K/K+1)+{1/(K+1)(K+2)}=(K+1)/K+2
K