sin(x+π/6)=1/2,则cos(π/3-x)
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos平方x.
sin(x+π/6)=1/2,则cos(π/3-x)
已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x
已知函数f(x)=cos(2x-π\3)+sin²x-cos²x
化简:1、sin(x-π/3)-cos(x+π/6)+√3cosx=?2、已知,sinα+sinβ=√2/2,求cosα
sin(x+1/2π)=cosx?还是cos-x
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1
已知函数f(x)=sin(2x+π/3)+sin(2x-π/3)+2cos^2x-1
函数f(x)=cos2x+cos(x+π/3)+sin(x+π/6)+3sin^2x的最小值
sin(x-π/3)=1/3,则cos(x+π/6)=?
求证 tan(2π-X)sin(-2π-X)cos(6π-X)/ sin(X+3π/2)*cos(X+3π/2)=-ta
已知函数f(x)=cos(π/6-2x)+cos(2x+π/6)+sin(2x+π/3)-sin(π/3-2x).