数列{an}满足an+1=(-1)n*an+n,则{an}的前100项和为多少?
数列{an}满足an+1=(-1)n*an+n,则{an}的前100项和为多少?
已知数列{an}满足a1=1,an-a(n+1)=ana(n+1),数列{an}的前n项和为Sn.(1)求证:{1/an
已知数列{an}的前n项和为Sn,且满足Sn=2an-1,n为正整数,求数列{an}的通项公式an
已知数列{an}满足a1=1,an+1=Sn+(n+1)(n∈N*),其中Sn为{an}的前n项和,
已知数列{an}的前n项和为Sn,且满足Sn=2an-1(n属于正整数),求数列{an}的通项公式an
数列{An}满足A1=1,An+1=An/2An+1 数列Bn的前n项和为Sn=12-12(2/3)n
已知数列{an}满足a1=2,a(n+1)=(5an-13)/(3an-7)则数列{an}的前100项的和是
数列an中,an=1/(根号(n+2)+根号n),则an的前n项和为
已知数列An满足An>0,其前n项和为Sn为满足2Sn=An的平方+An(1)求An(2)设数列Bn满足An/2的n次方
已知数列{An}满足2an+1=an+an+2,它的前n项和为An,且a3=5
已知数列{an}满足a1=1,an+1=2an/(an+2)(n∈N+),则数列{an}的通项公式为
已知数列{an}满足2an+1=an+an+2(n∈N*),它的前n项和为Sn,且a3=-6,S6=-30.求数列{an