A 1.778g sample of a component of the light petroleum distil

来源：学生作业帮编辑：作业帮分类：英语作业时间：2024/05/22 09:51:08

A 1.778g sample of a component of the light petroleum distillate called naphtha is found to yield5.450g CO2(g) and 2.602g H2O(l) on complete combustion.
Use the masses of carbon dioxide,CO2,and water,H2O,to determine the empirical formula of the alkane component.
Express your answer as a chemical formula.
写出化学式就好了我算出来的CH比是3：

CH比3：7,应该是己烷,C6H14
再问：那方程式是c6h14和o2生成二氧化碳和水吗？可是我输入后不对啊系数是2，19，12，14
再答：怎么不对啊，就是这个啊，亲，你不会把上面那个质量比跟下面的摩尔比放一块看了吧
再问：没有啊确实不对我也不知道
再答：答案是什么？
再问：我不知道我是输答案点check的现在只剩两次机会了
再答：额，它是不是要那个标准化学方程式啊，就是把系数除以2，C6H14+19/2O2=6CO2+7H20. 嘿嘿，你要不再问问别人

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