(1/3)^[log(1/2)^(x^2-3x+1)]
1/log(2)x+1/log(3)x+1/log(4)x=1,x=?
解不等式:log½(x²-1)>log½(2x²-x-3)
log(2x)+log(3y)-log(2z) 怎么化简? log3(x^2-2x-6)=2 log(3x+6)=1+l
已知log(1/7)[log(3)(log(2)x)]=0
2log底3x+log底3 2=1/2log底3 16 x为什么值
log底数7[log底数3(log底数2X)]=0,那么x^1/2的值是
(1/3)^[log(1/2)^(x^2-3x+1)]
(高一)若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{lo
请画出下列图像:log 1/2 (-x) y=log 1/3 /x/
2log的底数3^x-log的底数x^3=1
2log∨6x=1-log∨6 3,则x的值是什么
log以5为底(3x-2)>log以5为底(x+1)