java 如何count 数字出现的次数啊?

java 如何count 数字出现的次数啊?
意思就是 如何return 一个50以内的random数组中 10到20 的所有数,然后计算10到20的数的出现次数.
Takes the array created in item#5,and counts how many times each number occurred in the array,and then print the result.
For example:if the given array is {12,11,15,12,11,12} then the output should be
11 occurs = 2
12 occurs = 3
12 occurs = 1
这个有点迷糊：
Create an array of 256 characters ,and read a message character by character from keyboard and store them in the array up to 256 symbols.The method should return number of the characters stored in the array.
我的code：
public static void main(String[] args)
\x05{
\x05int [] numarray= new int [50];
\x05\x05for(int i=0;i

Create an array of 256 characters ,and read a message character by character from keyboard and store them in the array up to 256 symbols.The method should return number of the characters stored in the array.
这个是让你统计实际放入数组的字符个数呢.
Takes the array created in item#5,and counts how many times each number occurred in the array,and then print the result.
For example:if the given array is {12,11,15,12,11,12} then the output should be
11 occurs = 2
12 occurs = 3
12 occurs = 1
----------------------
public class Cat {
\x05public static void main(String[] args) {
\x05\x05int[] numarray = new int[50];
\x05\x05int[] count = new int[11]; //0~10,11,12
\x05\x05
\x05\x05for (int i = 0; i < numarray.length; i++) {
\x05\x05\x05numarray[i] = (int) (Math.random() * 50);
\x05\x05}
\x05\x05
\x05\x05count(numarray,count);
\x05\x05displaycount(count);
\x05}
\x05public static void count(int[] numArray,int[] count){
\x05\x05for(int i = 0; i < numArray.length;i++){
\x05\x05\x05
\x05\x05\x05if(numArray[i] == 20){
\x05\x05\x05\x05count[10] = count[10]+1;
\x05\x05\x05}else if(numArray[i] >= 10 && numArray[i] < 20){
\x05\x05\x05\x05count[numArray[i]%10] = count[numArray[i]%10] + 1;
\x05\x05\x05}
\x05\x05}
\x05
\x05}
\x05public static void displaycount(int[] count) {
\x05\x05for (int i = 0; i < count.length; i++) {
\x05\x05\x05System.out.println((i + 10) + ":" + count[i]);
\x05\x05}
\x05}
}
即可
再问： Create an array of 256 characters , and read a message character by character from keyboard and store them in the array up to 256 symbols. 跟之前要count的数字有关系吗？ 用ASCII去对比吗？ 不知道怎么对比啊！ printOneInLine(parameters) Pass the array created in item 7 to print each word of the message in a line. 我想print一个表，因为还有十个随机数，倒数 。可是现在的数字是一路下去求赐教！
再答： 1) 没有关系，这个是你定义了一个256长度的字符数组，然后你输入了10个字符，就返回10， 输入15就返回15； 2）不明白
再问： 就是像一个表一样，本来是 number 1 2 3 4 5 reverse 5 4 3 2 1。 我想让他成为 number reverse 1 5 2 4 3 3 4 2 5 1
再答： 存在数组里面的还是？ 如果是数组 int nums[] = {1, 2, 3, 4, 5}; for(int i = nums.length -1; i >= 0; i--){ System.out.println(nums[i]); } 即可。数组， list都可以这样处理。