求lim(x→0)(1+2x)^1/sinx值,
求极限: Lim x→0(1/sinx - 1/x)
求Lim(x→0)(sinx/x)^(cosx/1-cosx)
lim(x→0)(1-x^2-e^-x)/sinx
求lim(x→0)(1+2x)^1/sinx值,
求极限 ((sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1
用洛必达法则求极限 1,lim(x→0)arctanx-x/sinx^3 2,lim(x→0)lncosax/lncos
求lim(x→0)ln[1+e^x(sinx)^2]/√(1+x^2)-1
求极限lim(x→0)e^x-x-1/sinx^2
求lim(x→0)[(x^2sin1/x)/sinx]
lim(x→0)(1+sinx)^(1/2x)
求详细解:lim(x→0+) (1-cosx)^sinx
求下列极限:1)lim√(x)lnx (x->0+); 2)lim(sinx/x)^1/x (x->0+)