代数式2m=3n,则m/(m+n)-m/(m-n)-2n^2/(m^2-n^2)=

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/13 10:18:16

m/(m+n)-m/(m-n)-2n^2/(m^2-n^2)
= m(m-n)/(m^2-n^2)-m(m+n)/(m^2-n^2)-2n^2/(m^2-n^2)
= (m^2-mn-m^2-mn-2n^2)/(m^2-n^2)
= 2n(m+n)/(n+m)(n-m)
= 2n/(n-m)
2m=3n m=1.5n
2n/(n-m)=-4

已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=? 代数式2m=3n,则m/(m+n)-m/(m-n)-2n^2/(m^2-n^2)= 若(m-2n)/(2m+n)=3,则[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)] - {9(m-2n 已知m-2n/2m+n=5,求代数式3(m-2n)/2m+n－15(2m+n)/m-2n－2 当m-n/m+n=3时,求代数式(3m+3n/m-n)-(m-n/m+n)^2的值为多少? 已知m/n=5、,求（m/（m+n）)+(m/(m-n))-(n^2/(m^3-n^2)) m-n+2n^2/(m+n) (m-n)^2 +n(n- m) （m-n)+2n（m-n) [(m-n)^2*(m-n)^3]^2/(m-n)^4 （m-n)2(n-m)3(n-m)4化简计算(m+n)^3-(n+m)(m-n)^2