作业帮 > 数学 > 作业

如何解3x-3/x-2+x-5/x-8=3x-9/x-4+x-3/x-6

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/21 20:56:04
如何解3x-3/x-2+x-5/x-8=3x-9/x-4+x-3/x-6
(3x-3)/(x-2)+(x-5)/(x-8)=(3x-9)/(x-4)+(x-3)/(x-6)
(3x-3)/(x-2)-(3x-9)/(x-4)=(x-3)/(x-6)-(x-5)/(x-8)
3[(x-1)/(x-2) -(x-3)/(x-4)]=(x-3)/(x-6)-(x-5)/(x-8)
左右同时通分得
3[(x-1)(x-4)-(x-3)(x-2)]/(x-2)(x-4)=[(x-3)(x-8)-(x-5)(x-6)]/(x-6)(x-8)
3(x²-5x+4-x²+5x-6)/(x-2)(x-4) =(x²-11x+24-x²+11x-30)/(x-6)(x-8)
3×(-2)/(x-2)(x-4)=(-6)/(x-6)(x-8)
1/(x-2)(x-4)=1/(x-6)(x-8)
(x-2)(x-4)=(x-6)(x-8)
x²-6x+8=x²-14x+48
-6x+14x=48-8
8x=40
x=5