1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...1/(x+2005)(x+2006)

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/22 12:34:42

1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...1/(x+2005)(x+2006)=1/2x+4024

有等式1/(x+1)(x+2)=1/(x+1)-1/(x+2)
所以左边=1/(x+1)-1/（x+2）+1/(x+2)-1/(x+3).
=1/(x+1)-1/(x+2006)
后面就不用我说了吧左右移一下统分就可以了

x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x 1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...1/(x+2005)(x+2006) |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4) 1+x+x^2+x^3+.+x^99+x^100 |x^2-3x-4|>x+1 (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 若x^3+x^2+x+1=0,求代数式1+x+x^2+x^3+x^4+x^5+...+x^2006+x^2007的值 (x-1)^3(x+1)（x-2）/(x+4)