-½x²×(2xy²-4x²y²)-4x²y×(-xy),其

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/14 12:51:41

-½x²×(2xy²-4x²y²)-4x²y×(-xy),其中x=2 y=-1
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-½x²×(2xy²-4x²y²)-4x²y×(-xy)
=-x³y^2+2x^4y^2+4x^3y^2
=3x^3y^2+2x^4y^2
将x=2 y=-1带入
原式=3*8*1+2*16*1=24+32=56

-½x²×(2xy²-4x²y²)-4x²y×(-xy),其计算：(xy-x²)×x-y/xy x²/xy-x/y 3x²y+xy²-[2xy²-4x²y+（x²y-2xy²） (2x²y-3xy²)-3(x²y-2xy²)+2（x²y-4xy&# (-x-2y)(x²-2xy+4y²) 化简(x²y-4y²)/(x²+4xy+4y²)*[(4xy)/(x-2y)+x x-y/x²÷x²-2xy+y²/xy*（xy-x²） -3(xy-2x²)-[y²-(5xy-4x²)+2xy] 化简4xy-3y²-3x²+xy-3xy-2x²+x²-2y² 计算 2xy[4x²y²-3y（xy+x²y）-xy²] 1.化简：x²-4y²/x²+y²+2xy÷2y+x/x²+xy.