要懂英文和数学的.(1)Find asymptotes of g(x) if f(x) has asymptotes o
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/22 02:01:00
要懂英文和数学的.
(1)Find asymptotes of g(x) if f(x) has asymptotes of x = 11 and y = -7 where f(x) = 2g(x - 7) - 3
(2)Find and give the zeros and their multiplicities (in the same order as the zeros,of the following function f(x) = x^3+ x^2 - x - 1
希望高手能帮手!
我不是要翻译啊,好像好多人都误会了。
(1)Find asymptotes of g(x) if f(x) has asymptotes of x = 11 and y = -7 where f(x) = 2g(x - 7) - 3
(2)Find and give the zeros and their multiplicities (in the same order as the zeros,of the following function f(x) = x^3+ x^2 - x - 1
希望高手能帮手!
我不是要翻译啊,好像好多人都误会了。
修改啦,之前负号没瞧见:
第一题:f(x) = 2g(x - 7) - 3的渐进线是x=11,y= - 7.g(x)=(f(x+7)+3)/2的渐进线自然就是 x+7=11 和y=(-7+3)/2即x=4,y= - 2.理由你要去看渐进线的极限定义.
第二题:x^3+x^2-x-1=(x+1)(x^2-1)=(x+1)^2(x-1)所以zeros are:-1 and 1,multiplicity for -1 is 2 and the multiplicity for 1 is 1.很简单,multiplicity就是因式分解后的那个根对应的指数
第一题:f(x) = 2g(x - 7) - 3的渐进线是x=11,y= - 7.g(x)=(f(x+7)+3)/2的渐进线自然就是 x+7=11 和y=(-7+3)/2即x=4,y= - 2.理由你要去看渐进线的极限定义.
第二题:x^3+x^2-x-1=(x+1)(x^2-1)=(x+1)^2(x-1)所以zeros are:-1 and 1,multiplicity for -1 is 2 and the multiplicity for 1 is 1.很简单,multiplicity就是因式分解后的那个根对应的指数
要懂英文和数学的.(1)Find asymptotes of g(x) if f(x) has asymptotes o
g(x)=1-2X f(g(x))=(1-X)的平方/X的平方(X不等于0) f(o)=
If the function f given by f(x)=x3 has an average value of 9
一道大学英文数学题 find a formula for the inverse of f.f(x)=5 4x+7 f-
已知函数f(x)=lnx+a/x,g(x)=x,F(x)=f(1+e的x次方)-g(x),x属于R
设f(x)=2x+3 ,g(x+2)=f(x-1),求g(x)的表达式
find the inverse of the function:f(x)= (4x-1)/(2x+3)
若f(x)是偶函数,g(x)是奇函数,且f(x)+g(X)=x的平方+1/(x+1),求f(X)
已知函数f(x)=loga^(x+1),g(X)=logx^(1-X) (a>o,且a不等于1) (1)求函数f(x)+
懂英文和数学的进if the integer n odd,2n is divisible by twice as man
已知函数f(x)=xxx,g(x)=x+根号x.1)求证函数h(x)=f(x)-g(x)的零点个数
设f(x)可导.且f(x)导数>0,f(0)=0,f(a)=b,g(x)是f(X)的反函数,求∫f(x)dx(上a下o)