main( ) {int k=4,a=3,b=2,c=1;printf ("%d\n",k<a
main( ) {int k=4,a=3,b=2,c=1;printf ("%d\n",k<a
main () {int a=5,b=4,c=3,x;x=a>b>c;printf("%d\n&q
main( ) { int c=5;printf("%d\n",(c+=c,c+8,++c);}
以下程序的运行结果是.main(){int k=4,a=3,b=2,c=1;printf(“%d\n”,k
main() {int a=1,b=1,c=1,y; y=++a&&++b||++c ; printf("..
C语言 main() {int x,y; x=11/3;y=5; printf("%%d,%%%d\n...
#include void main() { int k=-1; printf("%d,%u\n",k,k); }
main() {int a[5]={2,4,6,8,10},*p,**k; p=a; k=&p; printf("%d"
我想知道main() {int a=1,b=2,c=3; printf(“%d,%d,%d,%d\n",a=b=c,a=
在C语言中 main() {int a=1,b=2,c=3; printf("%d,%d,%d,%d\n",a=b=c,
#define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k
fun(int k) {if(k>0)fun(k-1) printf("%d",k); } main() {int w=