求对数函数公式的推导log(a)(M^n)=nlog(a)(M) 和log(a)(N)=log(b)(N) / log(
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/02 03:14:24
求对数函数公式的推导
log(a)(M^n)=nlog(a)(M)
和log(a)(N)=log(b)(N) / log(b)(a) 的推导
log(a)(M^n)=nlog(a)(M)
和log(a)(N)=log(b)(N) / log(b)(a) 的推导
log(a)(M^n)
=log(a)(M*M*M*..M) (n个M)
=log(a)(M)+log(a)(M)+log(a)(M)+.+log(a)(M)(n个log(a)(M))
=nlog(a)(M)
log(a)(N)
=log(a)[b^log(b)(N)]
=log(b)(N) log(a)(b)
=log(b)(N) log(a)(a^log(b)(a))
=log(b)(N) / log(b)(a)
=log(a)(M*M*M*..M) (n个M)
=log(a)(M)+log(a)(M)+log(a)(M)+.+log(a)(M)(n个log(a)(M))
=nlog(a)(M)
log(a)(N)
=log(a)[b^log(b)(N)]
=log(b)(N) log(a)(b)
=log(b)(N) log(a)(a^log(b)(a))
=log(b)(N) / log(b)(a)
求对数函数公式的推导log(a)(M^n)=nlog(a)(M) 和log(a)(N)=log(b)(N) / log(
log(a)(M^n)=nlog(a)(M) 的推导
对数运算性质log(a)(M^n)=nlog(a)(M) (n∈R)是如何推导的?请不要用log(a)(MN)=log(
对数函数log(a)(M^n)=nlog(a)(M) (n∈R) 怎么推出的
对数换底公式证明?log a^m b^n= n/m log a b 为什么我证明出来是=m/nlog a b
对数换底公式;log(a) (m^n)=nlog(a) (m).
log(a^N)(b^M)=M/Nlog(a)(b)怎么推导?
证明:log(a)(M^n)=nlog(a)(M)
对数的公式log(a^n)^(b^m)=n/m log a b是怎么推的?
对数运算性质3的推导用^表示乘方,用log(a)(b)表示以a为底,b的对数log(a)(M^n)=nlog(a)(M)
证明:log(a)M*log(b)N=log(a)N*log(b)M.对调真数的位置,对数的积不变.
证明a(log(m)n)=n(log(m)a)