请教初一的数学题急求证:N=52*32n+1*2n-3n*3n*6n+2能被13整除.2 2n+1 n n n n+2分
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请教初一的数学题
急求证:N=52*32n+1*2n-3n*3n*6n+2能被13整除.
2 2n+1 n n n n+2分别是5 3 2 3 3 6的乘方.哪位朋友能列举解题步骤?谢谢!
急求证:N=52*32n+1*2n-3n*3n*6n+2能被13整除.
2 2n+1 n n n n+2分别是5 3 2 3 3 6的乘方.哪位朋友能列举解题步骤?谢谢!
是不是求证这个多项式能被13整除?
N=(5^2)*(3^2n+1)*(2^n)-(3^n)*(6^n+2)
=5^2*3^2n+1*2^n-3^n*(2*3)^n+2
=5^2*3^2n+1*2^n-3^n*2^n+2*3^n+2
=5^2*3^2n+1*2^n-3^n*2^n*2^2*3^n+1*3
=5^2*(3^2n+1*2^n)-(3^2n+1*2n)*2^2*3
=(25-12)*(3^2n+1*2^n)
=13*(3^2n+1*2^n)
我刚才就在做这道题……
N=(5^2)*(3^2n+1)*(2^n)-(3^n)*(6^n+2)
=5^2*3^2n+1*2^n-3^n*(2*3)^n+2
=5^2*3^2n+1*2^n-3^n*2^n+2*3^n+2
=5^2*3^2n+1*2^n-3^n*2^n*2^2*3^n+1*3
=5^2*(3^2n+1*2^n)-(3^2n+1*2n)*2^2*3
=(25-12)*(3^2n+1*2^n)
=13*(3^2n+1*2^n)
我刚才就在做这道题……
请教初一的数学题急求证:N=52*32n+1*2n-3n*3n*6n+2能被13整除.2 2n+1 n n n n+2分
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
Sn=n(n+2)(n+4)的分项等于1/6[n(n+2)(n+4)(n+5)-(n-1)n(n+2)(n+4)]吗?
N=52*32n+1*2-3n*6n+2能被13整除吗?
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
求证:对于任意自然数n,(n+5)-(n+2)(n+3)一定能被6整除
2^n/n*(n+1)
当n为正偶数,求证n/(n-1)+n(n-2)/(n-1)(n-3)+...+n(n-2).2/(n-1)(n-3)..
52•32n+1•2n-3n•6n+2能被13整除吗?
证明6能整除(6^n-3^n-2^n)-1,其中n为奇数
1 + (n + 1) + n*(n + 1) + n*n + (n + 1) + 1 = 2n^2 + 3n + 3
化简(n+1)(n+2)(n+3)