作业帮let a,b and c be rational numbers and b=0.24-0.26a,c=0.26-0.
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let a,b and c be rational numbers and b=0.24-0.26a,c=0.26-0.24a,then a^2-b^2+c^2=
原式=a²-（b²-c²）=a²-（b-c)（b+c）由于b是5分之12减去（5分之13）a,c是5分之13减去（5分之12）a,则上式=a²-（负5分之一减负五分之一a）（5-5a）=a²-【负五分之一（1+a）5（1-a）】=a²-【-（1+a）（1-a）】=a²-（a+1）（a-1）=a²-（a²-1）=a²-a²+1=1
别忘了给我加分,下面的那个人的是错的.
别忘了给我加分,下面的那个人的是错的.
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