(x²+4x)-(y²-4y)
(x-2y)²+(2x-4y)(x+y)+(x+y)²
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
(3x-y)²-2x(4x-5y)-(x+2y)²
已知x²+y²-8x+6y+25=0,求(x-y+4xy/x-y)(x+y-4xy/x+y)
2.(x+y)²(x-y)²-(x-y)(x+y)(x²+y²)
(x²+4x)-(y²-4y)
【(X²+Y²)-(X-Y)²+2Y(X-Y)】/4Y=1,求4X/4X²-Y&
4(x+y)²-20(x+y)+25
因式分解:25(x+y)²-9(x-y)²;(x+y)²-4(x+y-1).
因式分解 (1).(x+y)(x+y-6)+9 (2).x²-16y²-x-4y
计算4(x+y)^5(x-y)^4÷[2(x+y)³*(y-x)²]
(x+2y)(x-2y)*(x²-4y²)