微分方程(siny+y^2sinx)dx+(xcosy-2ycosx)dy=0.求详解.

微分方程(siny+y^2sinx)dx+(xcosy-2ycosx)dy=0.求详解. 求微分方程dy/dx=1/(xcosy+sin2y)满足y(-2)=0的特解 解微分方程 (siny-ysinx)dx+(xcosy+cosx)dy=0 (cosy+ycosx)dx+(sinx-siny)dy=0 dy/dx=-(2xcosy+y^2*cosx)/(2ysinx-x^2*siny) (2siny)dx+(2xcosy+1)dy是某个函数的全微分,求原函数 求解微分方程dy/dx +y=y^2(cosx-sinx) sinx+ siny=xy求dy/dx x-y+siny=2,求dy/dx ·(3x^2tany-y^2sinx)dx+(x^2sec^2y+2ycosx-4)dy=0如何求通解? dy/dx-ycosx=e^sinx 求微分方程dy/dx=-x/siny的解