H2的燃烧热是285.8kj/mol则2H2O=2H2+O2△H=571.6kj/mol为什么错了
H2的燃烧热是285.8kj/mol则2H2O=2H2+O2△H=571.6kj/mol为什么错了
1mol水蒸气转化为液态水放出45KJ,则H2(g)+1/2 O2(g)=H2O(g)△H= kj/mol.氢气的燃烧热
已知2H2(g)+O2(g)==2H2O(g) 则 H=-483.6kJ/mol ,则氢气的燃烧热为241.8KJ/mo
已知氢气的燃烧热为285.8KJ/ mol,H2(g)=H2(l),△H=-0.9KJ/mol;O2(g)=O2(l),
2H2(g) + O2 (g) = 2H2O(l) △H = - 571.6 kJ/mol
H2(g)+1//2O2(g)=H2O(l),焓值ΔH=-285.8KJ/mol是对1mol的H2说的吗?
已知2H2(g)+O2=2H2O(l)△H=-571.6kJ/mol,CO(g)+1/2O2(g)=-285.8kJ/m
2H2(g)+O2(g)=2H2O (l) H=-571.6kj/mol
H2(g)的燃烧热△H=_285.8KJ.mol_1,则2H2O(g)=2H2(g)+O2(g)△H=+571.6mol
已知:2H2(g)+O2(g)=2H2O(l) △H=-571.6kj/mol 2h2(g)+O2(g)=2H2O(g)
2H2(g)+O2(g)==2H2O(g) △H=-571.6kJ/mol
已知:2H2(g)+O2(g)=2H2O(l) △H=571.6kj/mol