m=x³-3x²y-2xy²+3y³
m=x³-3x²y-2xy²+3y³
先化简,再求值:{xy(x²-3y)+3xy²}(-2xy)+x³y²(2x-y
若m=x³-3x²y+2xy²+3y³,n=x³-2x²y+
一.x-y=2,则x²-2xy+y²= 二.x-y=-1,xy=3,则x³y-2x
-2y³+(3xy²-x²y)-2(xy²-y³)
先化简再求值,3xy²(xy+2y²-x²)+3x³y²,其中x=2,
x²-2xy+y²分之x²+2xy-3y³如何因式分解
计算:(-7x²y)(2x²y-3xy³+xy)
(3xy)² · (x²+xy-y²)-3xy(3x³y+3x²y
x+y=-3,xy=-2,求x³y²+x²y³的值
1、(m-n-3)² 2、x³y-4x²y²+3xy³
已知x+y=5,xy=3,x³+y³=(x+y)(x²-xy+y²),则1/x&