z=x*arctan(xy),求(dz/dx)|(1,1),(dz/dy)|(1,1)
z=x*arctan(xy),求(dz/dx)|(1,1),(dz/dy)|(1,1)
设Z=f(x^2 +y,2xy),求dz/dx和dz/dy
求由方程组x+y+z=0;x^2+y^2+z^2=1所确定的函数的倒数dx/dz,dy/dz
用matlab解微分方程组:dy/dz – z =cosx,dz/dx + y =1 .
设z=arctan(xy),y=e的x次方,求dz/dx
Z=(1+x^2+y^2),则dz(1,1)等于多少(dx+dy)
设z=u^2cosv^2,u=x+y,v=xy,求dz/dx,dz/dy.
设有方程x+y^2+z^2=2z,求dz/dx dz/dy
求函数:z^x=y^z的,dz/dx,dz/dy,
设x+y^2+z=ln(x+y^2+z)^1/2,求dz/dx
若z=e^(x^2+y^3),求dz/dx,dz/dy
z=(2y+7)^2 * ln(x^3+2) 求dz/dx 和 dz/dy