3^(log3 ^2)怎么计算
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
一道对数计算,log3(27/5)+log3(2/3)-log3(6/5)
log3(2)*log8(9)怎么计算?
log2(3)+log3(5)+log3(2)=?
log3/2乘以5log2/3怎么化简?
log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写
log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2)
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
计算:1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a
计算:log3 8×log4 27+5^(1-log5 2)+(27/8)^-(2/3)+sin3π/2
计算:log3底4次根号27/3+7^log7底2