[(x+2y)(x-2y)+4(x-y)²]÷6x
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
x(x-y)-y(y-x)+(x-y)²因式分解
{(x-y)²+(x+y)(x-y)}÷2x
因式分解x²(x-2y)+y²(2y-x)
(x-2y)²+(2x-4y)(x+y)+(x+y)²
1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(
[(2x+y)²-y(y+4x)-8x] ÷2x 其中x=2,y=-1
(2/3x-2/x+y(x+y/3x-x-y))÷x-y/x,其中5x+3y=0
{(x+2y)²—(x-2y)²-(x+2y)(x-2y)-4y²}÷2x求
已知2x-y=-6,求代数式[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]÷4x的值.
已知2x-y=-6,求代数式[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]÷4y的值.