1+2cos^α-cos2α怎么化简?
(2sin2α/1+cos2α)*(cosα)^2/cos2α=?
化简(sinα-cosα)^2-1/-cos2α
求sin²αsin²β+cos²αcos²β-1/2cos2αcos2β的值 化
化简:sin^2αsin^2β+cos^2αcos^2β-1/2cos2αcos2β
化解sin^2αsin^2β+cos^2αcos^2β-1/2cos2αcos2β
化简(sinα)^2*(sinβ)^2+(cosα)^2(cosβ)^2-1/2cos2αcos2β
Sin²αSin²β+Cos²αCos²β-1/2Cos2αCos2β
化简:sin²αsin²β+cos²αcos²β-1/2cos2αcos2β
sin²α*sin²β+cos²α*cos²β-1/2cos2αcos2β
化简:sin²αsin²β+cos²αcos²β—1/2cos2αcos2β
sin²αsin²β+cos²αcos²β-【(1/2)*cos2αcos2β】
化简 sin²αsin²β+cos²αcos²β-1/2(cos2αcos2β)