tan12°-3)/sin12°*[4(cos12°)^2-2]
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/16 13:47:50
tan12°-3)/sin12°*[4(cos12°)^2-2]
因为 4(cos12°)^2-2]=2[2(cos12°)^2-1] =2cos24°
(tan12°-根号3)=sin12°/cos12°-根号3=(sin12°-根号3cos12°)/cos12°
所以(tan12°-根号3)/sin12°*[4(cos12°)^2-2]
=(sin12°-根号3cos12°)/2sin12°cos12°*cos24°
=(sin12°-根号3cos12°)/sin24°*cos24°
=2(sin12°-根号3cos12°)/2sin24°*cos24°
=2(sin12°-根号3cos12°)/sin48°
=4(1/2*sin12°-根号3/2*cos12°)/sin48°
=4(cos60°*sin12°-sin60°*cos12°)/sin48°
=-4(sin60°*cos12°-cos60°*sin12°)/sin48°
=-4sin(60°-12°)/sin48°
=-4sin48°/sin48°
=-4.
(tan12°-根号3)=sin12°/cos12°-根号3=(sin12°-根号3cos12°)/cos12°
所以(tan12°-根号3)/sin12°*[4(cos12°)^2-2]
=(sin12°-根号3cos12°)/2sin12°cos12°*cos24°
=(sin12°-根号3cos12°)/sin24°*cos24°
=2(sin12°-根号3cos12°)/2sin24°*cos24°
=2(sin12°-根号3cos12°)/sin48°
=4(1/2*sin12°-根号3/2*cos12°)/sin48°
=4(cos60°*sin12°-sin60°*cos12°)/sin48°
=-4(sin60°*cos12°-cos60°*sin12°)/sin48°
=-4sin(60°-12°)/sin48°
=-4sin48°/sin48°
=-4.
求值:(根号3乘以tan12°-3)/【sin12°(4cos12°-2)】
tan12°-3)/sin12°*[4(cos12°)^2-2]
求值:(tan12°-根号3)/(sin12°(4cos12°-2))
根号3*tan12°-3/【(4cos12°-2)*sin12°】
(tan12°-根号3)/【(4*cos12°*cos12°)*sin12°
[(根号3)tan12°-3]÷【sin12°×[4(cos12°)^2 -2]】
求值:(√3tan12°-3)/(4(cos12°)^2-2)sin12°
18.求(√3tan12°-3)/sin12°(4cos12°的平方-2)
求(√3tan12°-3)/(sin12°X(4cos12°-2))的值
(√3tan12-3)/[sin12*(4(cos12)^2-2)]
求(√3tan12º-3)╱(sin12º(4cos12º-2))
根号3tan12减3/sin12(4cos12平方减2)的值为多少