8x+10y=12 8x+10y=110
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
已知实数x,y满足|x|+x+y=10、x+|y|-y=12,则x+y的值?
若x^2+y^2-8x-10y+41=0,求x/y+y/x的值
x^2+y^2-8x+10y+41=0求(x+y)^2013
已知x、y满足:x的平方+y的平方-6x+8y+25=0,求y/x-x/y的值
25X+12Y=7 10X-18Y=-4 3X+8Y=26 5X-12Y=37
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
已知X,Y为实数,且满足2X^2+4XY+4Y^2+8X+12Y+10=0,求x+y的值.
【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2=
解方程组2x+y+x=10 x+2y+z=-6 x+y+2z=8
4X-3Y-6=0和X平方+Y平方-18X+45=0组成方程组怎么解?5X+12Y+10=0和X平方+Y平方-8X+6Y
已知/x/+x+y=10,/y/+x-y=12.求x+y的值