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1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3).+1/(X+99)(X+100)=

来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/16 13:58:39
1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3).+1/(X+99)(X+100)=
1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3).+1/(X+99)(X+100)
=1/X - 1/(X+1) + 1/(X+1) - 1/(X+2) + 1/(X+2) - 1/(X+3) + .+ 1/(X+99) - 1/(X+100)
= 1/x - 1/(x+100)
= 100/x(x+100)
1+x+x^2+x^3+.+x^99+x^100 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x 1X+2X+3X…+98X+99X+100X=50500X X等于多少? 1x+2x+3x+4x+5x+6x+7x…+99x=100 解方程：2x+4x+6x...+100x=1-(x+3x+5x+...+99x) x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) 已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^96的值 x/x平方-x+2=2x/x+1 分解公因式(1+X)+X(1+X)+X(1+X)^2+X(1+X)^3+...+X(1+X)^99 x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002