1\x(x+1)+1\(x+1)(x+2)+1\(x+2)(x+3)+----+1\(x+2012)(x+2013)

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/23 17:38:38

1\x(x+1)+1\(x+1)(x+2)+1\(x+2)(x+3)+----+1\(x+2012)(x+2013)
=1/x-1/(x+1)+1/(x+1)-1/(x+2)+.+1/(x+2012)-1/(x+2013)
=1/x-1/(x+2013)
=2013/x(x+2013)
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x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x 1+x+x^2+x^3+.+x^99+x^100 |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| {2X+1}+{X} x^2-|x|+1 ｜x-1｜+｜x-2｜已知x^2+x=-1 你能求x^2013+x^2012+x^2011+x^2010+x^2009+…+x^4+x^3+x x(x+1)^3+x(x+1)^2+x(x+1)+x+1因式分解 x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4) 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)