S
∵等差数列{an}{bn}的前n项和分别为Sn,Tn, ∵ Sn Tn= 2n n+1, ∴则 a7 b7= s13 T13= 26 14= 13 7, 故答案为: 13 7
已知等差数列{an},{bn}的前n项和分别为Sn和Tn,若S
等差数列{an},{bn}的前n项和分别为Sn和Tn,若S
已知等差数列{an}{bn}的前n项和分别为Sn,Tn,若S
若两个等差数列{an}和{bn}的前n项和分别为Sn和Tn,且满足S
两个等差数列{an}和{bn}的前n项和分别为Sn和Tn,若S
若两个等差数列{an},{bn}的前n项和分别为Sn,Tn,且满足S
两等差数列{an}和{bn},前n项和分别为Sn,Tn,且S
等差数列{an},{bn}的前n项和分别为Sn,Tn,若Sn/Tn=2n/3n+1,求an/bn的表达式
等差数列{an},{bn}的前n项和分别为Sn,Tn,若Sn/Tn=2n/3n+1 ,则an/bn=
等差数列{an}、{bn}的前n项和分别为Sn、Tn,若Sn/Tn=2n/3n+1,求an/bn
两个等差数列{an},{bn}的前n项和分别为Sn,Tn,若Sn/Tn=2n/3n+1,求an/bn.
已知等差数列{an}、{bn}的前n项和分别为Sn、Tn,若Sn/Tn=【7n+1】/【4n+27】,则an/bn=
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