已知函数f(x),g(x)同时满足:g(x-y)=g(x)g(y)+f(x)f(y);f(-1)=-1,f(0)=0,f
已知函数f[x],g[x]同时满足:g[x-y]=g[x]g[y]+f[x]f[y];f[-1]=-1,f[0]=0,f
f(x-y)=f(x)g(y) - g(x)f(y) 且f(-2)=f(1)不等于0 ,则g(1)+g(-1)=?
1.若f(x)和g(x)都是定义在R上的函数,且满足f(x-y)=f(x)g(y)-g(x)f(y),f(-2)=f(1
已知函数f(x),g(x)在R上有定义,对任意的x,y属于R有f(x-y)=f(x)g(y)-g(x)f(y)且f(1)
已知二次函数f(x)满足:f(0)=0,且f(x+1)=f(x)=x+1,g(x)=2f(-x)+x,
已知函数y=g(x)与f(x)=loga(x+1)(0
已知函数f(x)=x+2,g(x)=x^2-x-6,求当满足f(x)大于g(x)时,y=g(x)+1/f(x)的最小值
复合函数的求导中y=f[g(x)],y'=f'[g(x)]•g'(x)为什么是f'[g(x)]乘以g'(x)
已知二次函数f(x)满足f(0)=0,且f(x+1)=f(x)+x+1,g(x)=2f(-x)+x 求f(x),f[g(
已知f(x),g(x)都是定义在R上的函数,对任意x,y满足f(x-y)=f(x)*(gy)-g(x)*f(y),且f(
函数y=f(x)满足f(u+v)=f(u)f(v),且f(1/2)=3,函数g(x)满足g(uv)=g(u)+g(v),
1.已知函数f(x),g(x)在R上有定义,对任意的x,y ∈R有f(x-y)=f(x)g(y)-g(x)f(y) 且f