integrate tan2x-sec2x / 2(tan2x)^2 dx
设y=(tan2x)^cot(x/2) ,求dy/dx
求证tanx-1/tanx=-2/tan2x
tan2x=-2√2 且满足 π/4
求证:(sinx+cosx)(1-tanx)=2sinx/tan2x
tanx=1/2,tan2x值只为?
知道tanX=2 ,如何求tan2X=?
(cos^2 2x-sin^2 2x)/(1-tan2x)=(1+2sin2xcos2x)/(1+tan2x)
求证(tanxtan2x/tan2x-tanx)/(tan2x-tanx)+√3(sin^2x-cos^2x)=2sin
lim(x→0)ln tan7x/ln tan2x= lim(x->0) [7(tan2x)·cos²2x]/
设n>=2,当x不等于k派,求证:tanx*tan2x+tan2x*tan3x+.+tan(n-1)*tannx=tan
三角函数微积分y=(1+tan2x) /(1-tan2x)求dy/dx
化简tanx+tan2x+tanx*tan2x*tan3x