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1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=?

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/10 11:12:38
1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=?
1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)
=(1/2){[1/x(x+1) - 1/(x+1)(x+2)] + [1/(x+1)(x+2) - 1/(x+2)(x+3)]+.
+[1/(x+98)(x+99) - 1/(x+99)(x+100)]}
=(1/2){1/x(x+1) - 1/(x+99)(x+100)}
=[(x+99)(x+100) - x(x+1)]/2x(x+1)(x+99)(x+100)
=[198x+9900]/2x(x+1)(x+99)(x+100)
=[99x+4950]/x(x+1)(x+99)(x+100)
=99(x+50)/x(x+1)(x+99)(x+100)